This problem solving activity has a measurement focus.
Moana set her digital watch at 13:00:00 on the last day of April.
Unfortunately the watch loses 11 seconds a day.
What is the time on Moana’s watch when it is 13:00:00 on the last day of May?
To solve this problem students must know the number of days in each month, that there are 60 minutes in an hour, that there are 60 seconds in a minute, and must be able to work between units of time.
Moana set her digital watch at 13:00:00 on the last day of April. Unfortunately the watch loses 11 seconds a day. What is the time on Moana’s watch when it is 13:00:00 on the last day of May?
What if the watch lost 11 seconds an hour. What would the time read on Moana's watch?
Since there are 31 days between the last day of April and the last day of May, Moana’s watch will have lost 31 x 11 = 341 seconds. To convert this into minutes, divide by 60. Hence 341 seconds = 5 minutes and 41 seconds. Then subtract 5 minutes 41 seconds from 13:00:00. This gives 12:54:19. This is the time on Moana’s watch.
Printed from https://meaningfulmaths.nt.edu.au/mmws/nz/resource/moana-s-watch at 8:57pm on the 26th February 2024